Defined in header <stdlib.h> | ||
---|---|---|
void* malloc( size_t size ); |
Allocates size
bytes of uninitialized storage.
If allocation succeeds, returns a pointer to the lowest (first) byte in the allocated memory block that is suitably aligned for any object type with fundamental alignment.
If size
is zero, the behavior is implementation defined (null pointer may be returned, or some non-null pointer may be returned that may not be used to access storage, but has to be passed to free
).
A previous call to | (since C11) |
size | - | number of bytes to allocate |
On success, returns the pointer to the beginning of newly allocated memory. To avoid a memory leak, the returned pointer must be deallocated with free()
or realloc()
.
On failure, returns a null pointer.
#include <stdio.h> #include <stdlib.h> int main(void) { int *p1 = malloc(4*sizeof(int)); // allocates enough for an array of 4 int int *p2 = malloc(sizeof(int[4])); // same, naming the type directly int *p3 = malloc(4*sizeof *p3); // same, without repeating the type name if(p1) { for(int n=0; n<4; ++n) // populate the array p1[n] = n*n; for(int n=0; n<4; ++n) // print it back out printf("p1[%d] == %d\n", n, p1[n]); } free(p1); free(p2); free(p3); }
Output:
p1[0] == 0 p1[1] == 1 p1[2] == 4 p1[3] == 9
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