numpy.left_shift(x1, x2, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'left_shift'>
Shift the bits of an integer to the left.
Bits are shifted to the left by appending x2
0s at the right of x1
. Since the internal representation of numbers is in binary format, this operation is equivalent to multiplying x1
by 2**x2
.
Parameters: |
x1 : array_like of integer type Input values. x2 : array_like of integer type Number of zeros to append to out : ndarray, None, or tuple of ndarray and None, optional A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or where : array_like, optional Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone. **kwargs For other keyword-only arguments, see the ufunc docs. |
---|---|
Returns: |
out : array of integer type Return |
See also
right_shift
binary_repr
>>> np.binary_repr(5) '101' >>> np.left_shift(5, 2) 20 >>> np.binary_repr(20) '10100'
>>> np.left_shift(5, [1,2,3]) array([10, 20, 40])
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Licensed under the NumPy License.
https://docs.scipy.org/doc/numpy-1.14.2/reference/generated/numpy.left_shift.html