Expanding.std(ddof=1, *args, **kwargs) [source]
Calculate expanding standard deviation.
Normalized by N-1 by default. This can be changed using the ddof argument.
| Parameters: |
ddof : int, default 1 Delta Degrees of Freedom. The divisor used in calculations is *args, **kwargs For NumPy compatibility. No additional arguments are used. |
|---|---|
| Returns: |
Series or DataFrame Returns the same object type as the caller of the expanding calculation. |
See also
Series.expanding DataFrame.expanding Series.std DataFrame.std numpy.std
The default ddof of 1 used in Series.std is different than the default ddof of 0 in numpy.std.
A minimum of one period is required for the rolling calculation.
>>> s = pd.Series([5, 5, 6, 7, 5, 5, 5]) >>> s.rolling(3).std() 0 NaN 1 NaN 2 0.577350 3 1.000000 4 1.000000 5 1.154701 6 0.000000 dtype: float64
>>> s.expanding(3).std() 0 NaN 1 NaN 2 0.577350 3 0.957427 4 0.894427 5 0.836660 6 0.786796 dtype: float64
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http://pandas.pydata.org/pandas-docs/version/0.23.4/generated/pandas.core.window.Expanding.std.html